
Khi ch\u01a1i l\u00f4 \u0111\u1ec1 m\u1ed7i ng\u01b0\u1eddi ch\u01a1i th\u01b0\u1eddng ch\u1ecdn cho m\u00ecnh nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p kh\u00e1c nhau \u0111\u1ec3 t\u0103ng kh\u1ea3 n\u0103ng \u0103n v\u00e0 l\u00e3i c\u1ee7a m\u00ecnh. B\u1ea1n \u0111\u00e3 t\u1eebng nghe v\u1ec1 c\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t m\u00e0 ch\u01b0a bi\u1ebft c\u1ee5 th\u1ec3 l\u00e0 nh\u01b0 th\u1ebf n\u00e0o, th\u00ec b\u00e0i vi\u1ebft n\u00e0y \u0111\u00edch th\u1ecb d\u00e0nh cho b\u1ea1n.<\/p>\n
B\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t l\u00e0 m\u1ed9t trong nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p h\u1eefu hi\u1ec7u gi\u00fap ng\u01b0\u1eddi ch\u01a1i v\u00e0o c\u1ea7u h\u1ee3p l\u00fd nh\u1ea5t. Ch\u00ednh v\u00ec th\u1ebf \u0111\u00e2y l\u00e0 ph\u01b0\u01a1ng ph\u00e1p \u0111\u01b0\u1ee3c nh\u1eefng ng\u01b0\u1eddi ch\u01a1i chuy\u00ean nghi\u1ec7p \u01b0u ti\u00ean l\u1ef1a ch\u1ecdn. \u0110\u1ec3 s\u1eed d\u1ee5ng c\u00e1ch b\u1eaft t\u1ed5ng l\u00f4 \u0111\u1eb7c bi\u1ec7t<\/strong> hi\u1ec7u qu\u1ea3 ng\u01b0\u1eddi ch\u01a1i c\u1ea7n th\u1eadt nhanh nh\u1ea1y v\u00e0 k\u0129 c\u00e0ng.<\/p>\n B\u1eaft t\u1ed5ng l\u00f4 \u0111\u1eb7c bi\u1ec7t \u0111\u01b0\u1ee3c t\u00ednh to\u00e1n nh\u01b0 sau: \u0110\u1ea7u ti\u00ean x\u00e1c \u0111\u1ecbnh m\u1ed1c ng\u00e0y b\u1eaft \u0111\u1ea7u t\u00ednh ta c\u00f3: gi\u1ea3 s\u1eed coi \u0111\u1ec1 ng\u00e0y th\u1ee9 nh\u1ea5t l\u00e0 AB, \u0111\u1ec1 v\u1ec1 ng\u00e0y th\u1ee9 hai l\u00e0 CD.<\/p>\n Ta c\u00f3 A + B = E; C + D = F.<\/p>\n \u0110\u1ec3 b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t hi\u1ec7u qu\u1ea3 b\u1ea1n c\u00f3 th\u1ec3 x\u00e9t \u1edf c\u00e1c tr\u01b0\u1eddng h\u1ee3p x\u1ea3y ra nh\u01b0 sau:<\/p>\n B\u1ea1n c\u00f3 th\u1ec3 xem x\u00e9t n\u1ebfu nh\u01b0 E < 10, F < 10 l\u1ea5y 10 \u2013 E = X, 10 \u2013 F = Y. \u0110\u00e1nh XY cho l\u00f4 c\u1ee7a ng\u00e0y th\u1ee9 3.<\/p>\n Trong tr\u01b0\u1eddng h\u1ee3p n\u00e0y n\u1ebfu nh\u01b0 E > 10, F < 10 l\u1ea5y 20 \u2013 E = X, 10 \u2013 F = Y, \u0111\u00e1nh l\u00f4 XY cho ng\u00e0y th\u1ee9 3.<\/p>\n N\u1ebfu nh\u01b0 E > 10, F > 10 th\u00ec l\u1ea5y 20 \u2013 E = X, 20 \u2013 F = Y, khi \u0111\u00f3 \u0111\u00e1nh l\u00f4 ng\u00e0y th\u1ee9 3 l\u00e0 XY.<\/p>\n N\u1ebfu E < 10, F > 10 th\u00ec ta l\u1ea5y hi\u1ec7u 10 \u2013 E = X, 20 \u2013 F = Y, tr\u01b0\u1eddng h\u1ee3p n\u00e0y ng\u01b0\u1eddi ch\u01a1i s\u1ebd l\u1ef1a ch\u1ecdn \u0111\u00e1nh YX trong ng\u00e0y th\u1ee9 3 \u0111\u00e1nh.<\/p>\n Khi E = 0 ho\u1eb7c 10, F = 0 ho\u1eb7c 10 th\u00ec X, Y \u0111\u1ec1u l\u00e0 0.<\/p>\n C\u1ea7u n\u00e0y c\u00f3 th\u1ec3 \u0111\u00e1nh li\u00ean t\u1ee5c trong 3 \u2013 4 ng\u00e0y. N\u1ebfu nh\u01b0 ng\u00e0y h\u00f4m sau \u0111\u00e1nh m\u00e0 kh\u00f4ng v\u1ec1 th\u00ec ngh\u1ec9 1 ng\u00e0y, nh\u01b0ng n\u1ebfu c\u1ea7u l\u1ea1i ra \u0111\u00fang h\u00f4m ngh\u1ec9 th\u00ec b\u1ecf c\u1ea7u lu\u00f4n, c\u00f2n n\u1ebfu nh\u01b0 v\u1eabn kh\u00f4ng ra th\u00ec h\u00f4m ti\u1ebfp s\u1ebd v\u1ec1.<\/p>\n Trong tr\u01b0\u1eddng h\u1ee3p k\u1ebft qu\u1ea3 v\u1ec1 l\u1ed9n th\u00ec ngh\u1ec9 3, 4 ng\u00e0y r\u1ed3i m\u1edbi \u0111\u00e1nh l\u1ea1i c\u1ea7u n\u00e0y. N\u1ebfu c\u1ea7u n\u00e0y kh\u00f4ng v\u1ec1 trong 5, 6 ng\u00e0y th\u00ec ng\u01b0\u1eddi ch\u01a1i s\u1ebd ngh\u1ec9 ng\u00e0y th\u1ee9 7 sau \u0111\u00f3 \u0111\u00e1nh 3 ng\u00e0y ti\u1ebfp, khi th\u1ea5y ng\u00e0y th\u1ee9 7 ra th\u00ec \u0111\u00e1nh c\u1ea7u n\u00e0y v\u00e0o ng\u00e0y th\u1ee9 8.<\/p>\n M\u1ed7i ph\u01b0\u01a1ng ph\u00e1p \u0111\u1ec1u c\u00f3 nh\u1eefng \u01b0u nh\u01b0\u1ee3c \u0111i\u1ec3m ri\u00eang, ch\u00ednh v\u00ec th\u1ebf \u0111\u1ec3 t\u00ednh to\u00e1n m\u1ed9t c\u00e1ch chu\u1ea9n x\u00e1c nh\u1ea5t ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 l\u1ef1a ch\u1ecdn ph\u01b0\u01a1ng ph\u00e1p ph\u00f9 h\u1ee3p v\u1edbi m\u00ecnh nh\u1ea5t.<\/p>\n Khi ch\u01a1i l\u00f4 \u0111\u1ec1 n\u00f3i chung trong l\u00f4 \u0111\u1ec1 kh\u00f4ng c\u00f3 kh\u00e1i ni\u1ec7m \u201ccao th\u1ee7\u201d v\u00e0 c\u0169ng kh\u00f4ng c\u00f3 c\u00e1ch n\u00e0o c\u00f3 th\u1ec3 gi\u00fap b\u1ea1n 100% tr\u00fang s\u1ed1. Vi\u1ec7c t\u00ednh to\u00e1n ch\u1ec9 gi\u00fap b\u1ea1n t\u0103ng t\u1ec9 l\u1ec7 tr\u00fang l\u00f4, \u0111\u1ec3 tr\u00fang l\u00f4 c\u00f2n m\u1ed9t ph\u1ea7n d\u1ef1a v\u00e0o v\u1eadn may c\u1ee7a ng\u01b0\u1eddi ch\u01a1i.<\/p>\n<\/div>\n<\/article>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\nC\u00e1ch b\u1eaft t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t t\u00ednh l\u00f4 ch\u00ednh x\u00e1c cao<\/strong><\/span><\/h2>\n
Tr\u01b0\u1eddng h\u1ee3p 1: <\/strong><\/span><\/h3>\n
Tr\u01b0\u1eddng h\u1ee3p 2:<\/strong><\/span><\/h3>\n
Tr\u01b0\u1eddng h\u1ee3p 3:<\/strong><\/span><\/h3>\n
Tr\u01b0\u1eddng h\u1ee3p 4:<\/strong><\/span><\/h3>\n
Tr\u01b0\u1eddng h\u1ee3p 5:<\/strong><\/span><\/h3>\n
K\u1ebft lu\u1eadn<\/strong><\/span><\/h2>\n
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